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Find the x-intercepts.
2x² - 3x + 1
y = 2x² + 8x + 6
у
(0.5, [?]). ([ ], [ ]

Find the x-intercepts. 2x² - 3x + 1 y = 2x² + 8x + 6 у (0.5, [?]). ([ ], [ ]-example-1
User Sgrove
by
8.4k points

2 Answers

3 votes

Answer:

Explanation:

To find the x-intercepts of a function, we set y = 0 and solve for x.

For the function 2x² - 3x + 1:

2x² - 3x + 1 = 0

We can use the quadratic formula to solve for x:

x = [ -(-3) ± sqrt( (-3)² - 4(2)(1) ) ] / (2*2)

x = [ 3 ± sqrt(1) ] / 4

x = 1/2 or x = 1

Therefore, the x-intercepts are (1/2, 0) and (1, 0).

For the function y = 2x² + 8x + 6:

2x² + 8x + 6 = 0

We can simplify this equation by dividing both sides by 2:

x² + 4x + 3 = 0

This equation factors as:

(x + 3)(x + 1) = 0

So the solutions are x = -3 and x = -1.

Therefore, the x-intercepts are (-3, 0) and (-1, 0).

For the coordinates (0.5, [?]).

To find the y-coordinate of the point (0.5, [?]), we can substitute x = 0.5 into the equation for the function:

y = 2(0.5)² + 8(0.5) + 6

y = 2(0.25) + 4 + 6

y = 5.5

Therefore, the coordinates are (0.5, 5.5).

For the coordinates ([ ], [ ]).

Without knowing the specific function, we cannot determine the x-intercepts or any other information about the graph. We would need to know the equation of the function or have additional information about the graph.

User Jos Vinke
by
8.2k points
5 votes

Answer:

(½,0),(1,0)

...............

User Josh Hull
by
8.3k points