Question

Boyle's Law states that the pressure exerted by a gas held at a constant temperature varies inversely with the volume of the gas. At a volume of 4 L the pressure of a gas is 112 kPa. If the volume of the gas is 16 Lwhat would be the pressure of the gas in kPa? (Write your answer as a whole number)

Answer 1

the pressure of the gas at a volume of 16 L would be 28 kPa.

Explanation:

Using Boyle's Law:

P1V1 = P2V2

Where:

P1 = 112 kPa (initial pressure)

V1 = 4 L (initial volume)

V2 = 16 L (final volume)

Solving for P2:

P2 = (P1 x V1) / V2

P2 = (112 kPa x 4 L) / 16 L

P2 = 28 kPa

Therefore, the pressure of the gas at a volume of 16 L would be 28 kPa.