Answer:
If (x-1) is a factor of the polynomial f(x) = 4x² - 4x² - x - K, then we know that (x-1) divides evenly into the polynomial, which means that the polynomial can be written as:
f(x) = (x-1)(ax + b)
where a and b are constants that we need to determine. We can use the distributive property to expand this expression and equate it with the original polynomial:
f(x) = (x-1)(ax + b) = 4x² - 4x - K
Expanding the left side of the equation, we get:
ax² + bx - ax - b = ax² - (a-b)x - b = 4x² - 4x - K
Now we can equate the coefficients of the like terms on both sides of the equation.
The coefficient of x^2 on the left side is a, and on the right side it is 4. Therefore, we have:
a = 4
The coefficient of x on the left side is b - a, and on the right side it is -4. Therefore, we have:
b - a = -4
Substituting a=4, we get:
b - 4 = -4
Solving for b, we get:
b = 0
So the polynomial can be written as:
f(x) = (x-1)(4x + 0) = 4x² - 4x
Therefore, K = 0.
To find the roots of the equation, we need to set f(x) = 0 and solve for x:
4x² - 4x = 0
Factor out 4x:
4x(x - 1) = 0
So the roots of the equation are x = 0 and x = 1.