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What are [Cu+] and [CN−] in a saturated CuCN solution if the Ksp of CuCN is
4x10^−20?

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Answer:

The solubility product constant, Ksp, for the reaction of copper(I) cyanide (CuCN) in water is given as 4x10^−20. The balanced chemical equation for this reaction is:

CuCN (s) ↔ Cu+ (aq) + CN− (aq)

The Ksp expression for this reaction is:

Ksp = [Cu+][CN−]

At equilibrium, the solution is saturated with CuCN, which means that the concentration of CuCN is equal to its solubility (S), and the concentrations of Cu+ and CN− are equal to x (the amount that dissolves). Thus, we can write:

CuCN (s) ↔ Cu+ (aq) + CN− (aq)

I S x x

The solubility of CuCN is equal to the amount that dissolves, which is equal to the initial concentration of Cu+ and CN− in the solution. Therefore:

[S] = [Cu+] = [CN−] = x

Substituting these values into the Ksp expression, we get:

Ksp = [Cu+][CN−] = x^2

Solving for x, we get:

x = sqrt(Ksp) = sqrt(4x10^-20) = 2x10^-10

Therefore, the concentrations of Cu+ and CN− in a saturated CuCN solution are both 2x10^-10 mol/L.

User Habib Rayan
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