Question

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The pressure on a 5.0 L tank of oxygen changes from 105 kPa to 45 kPa. If the temperature hasn't changed, what is the volume of the gas?

Answer 1

To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas:

P1V1/T1 = P2V2/T2

where P1, V1, and T1 are the initial pressure, volume, and temperature, and P2, V2, and T2 are the final pressure, volume, and temperature.

We are given:

P1 = 105 kPa

V1 = 5.0 L

P2 = 45 kPa

T1 = T2 (temperature is constant)

We need to find V2, the final volume.

Substituting the given values into the combined gas law equation, we get:

(105 kPa)(5.0 L)/T = (45 kPa)V2/T

Simplifying, we get:

V2 = (105 kPa)(5.0 L)/(45 kPa) = 11.7 L

Therefore, the volume of the gas is 11.7 L when the pressure changes from 105 kPa to 45 kPa, assuming the temperature remains constant.