Question

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If you have 40 L of a gas at 6 atm, and 275K, how many moles will you have?(R=0.0821atm*L/mol*K)

Answer 1

The ideal gas law is PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

We have P = 6 atm, V = 40 L, T = 275 K, and R = 0.0821 atmL/molK.

Rearranging the ideal gas law, we get:

n = PV/RT

Substituting the values we have:

n = (6 atm * 40 L) / (0.0821 atmL/molK * 275 K)

n = 9.49 moles

Therefore, we have 9.49 moles of gas in the 40 L container.