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The pressure in an automobile tire is 1.88 atm at 25.0°C. What will the pressure be if the temperature warms up to 37.0°C?

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Answer:

To solve this problem, we can use the ideal gas law, which relates the pressure, volume, number of moles, and temperature of a gas:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

We are given:

P1 = 1.88 atm

T1 = 25.0°C = 298.15 K

We need to find P2, given:

T2 = 37.0°C = 310.15 K

We can assume that the volume and number of moles of gas remain constant.

Substituting these values into the ideal gas law equation, we get:

P1V = nRT1

P2V = nRT2

Dividing the second equation by the first equation, we get:

P2/P1 = T2/T1

Substituting the values we have, we get:

P2/1.88 atm = 310.15 K/298.15 K

Solving for P2, we get:

P2 = (1.88 atm) x (310.15 K)/(298.15 K) = 1.96 atm

Therefore, the pressure in the tire will be 1.96 atm if the temperature warms up to 37.0°C.

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