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you find that a distant galaxy is moving away from us a 407 km/s. what is the distance to the galaxy (in mpc)?

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Answer:

Approximately
6\; {\rm Mpc} (assuming that
H_(0) \approx 70\; {\rm km \cdot s^(-1) \cdot Mpc^(-1)}.)

Step-by-step explanation:

The speed at which a distant object moves away from the observer is known as recessional velocity.

By Hubble's law, the recessional velocity
v of a distant galaxy would be proportional to the distance
D from the observer:


v = H_(0)\, D,

Where
H_(0) is Hubble's Constant.

The value of Hubble's Constant varies over time. Assuming that
H_(0) \approx 70\; {\rm km \cdot s^(-1) \cdot Mpc^(-1)}. Rearrange Hubble's Law to find distance
D:


\begin{aligned}D &= (v)/(H_(0)) \\ &\approx \frac{407\; {\rm km\cdot s^(-1)}}{70\; {\rm km\cdot s^(-1) \cdot Mpc^(-1)}} \\ &\approx 6\; {\rm Mpc}\end{aligned}.

User Ilya Evdokimov
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