Question

nitrogen and hydrogen gas react to form ammonia gas. suppose you have 13.0 mol of n2 and 9.0 mol of h2 in a reactor. suppose as much of the n2 reacts. how much will be left

Answer 1

After reacting 13.0 moles of nitrogen with 9.0 moles of hydrogen to form ammonia, there will be 10.0 moles of nitrogen leftover, as hydrogen is the limiting reagent in this reaction.

Step-by-step explanation:

The question asks about the amount of nitrogen leftover after a reaction with hydrogen to form ammonia. Based on the balanced chemical reaction N2 + 3 H2 → 2 NH3, each mole of nitrogen reacts with three moles of hydrogen to form two moles of ammonia. With 13.0 moles of N2 and 9.0 moles of H2 in a reactor, we can see that hydrogen is the limiting reagent because we would need 39 moles of hydrogen to fully react with the nitrogen (13.0 moles N2 * 3 moles H2 / 1 mole N2). Since we only have 9.0 moles of hydrogen, we use this to calculate the nitrogen consumed: 9.0 moles H2 * 1 mole N2 / 3 moles H2 = 3 moles N2. Subtracting this from the initial 13.0 moles of nitrogen, we find that there will be 10.0 moles of nitrogen left over after the reaction.