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A light source at a height of 8 metres is shining a laser beam onto the mirror on the ground. The light beam needs to be observed by a sensor at a height of 4 metres. If the total distance the laser beam travels is 15 metres, what is the distance between the bases of the light source and the sensor? Your answer should be a numerical value.

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Using the Pythagorean theorem, we can find the distance between the bases of the light source and the sensor. Let's call this distance "x".

We know that the light source is at a height of 8 metres and the sensor is at a height of 4 metres, so the vertical distance between them is 8 - 4 = 4 metres.

We also know that the total distance the laser beam travels is 15 metres. Let's call the horizontal distance between the mirror and the sensor "y". Then, the horizontal distance between the light source and the mirror is also "y".

Using the Pythagorean theorem, we can create an equation:

x^2 = y^2 + 4^2 (equation 1)
x^2 = y^2 + (15-y)^2 (equation 2)

We can simplify equation 2 by expanding (15-y)^2:

x^2 = y^2 + (225 - 30y + y^2)

Combining like terms:

x^2 = 2y^2 - 30y + 225

Now we can substitute equation 1 into this equation:

y^2 + 4^2 = 2y^2 - 30y + 225

Simplifying:

y^2 + 16 = 2y^2 - 30y + 225

Rearranging and simplifying:

y^2 - 30y + 209 = 0

Using the quadratic formula:

y = (30 ± sqrt(30^2 - 4*1*209)) / (2*1)
y = (30 ± sqrt(16)) / 2
y = 15 ± 2

Since we're looking for a positive value for "y", we can take the solution y = 15 - 2 = 13.

Now we can substitute this value of "y" into equation 1:

x^2 = 13^2 + 4^2
x^2 = 185
x = sqrt(185)

Therefore, the distance between the bases of the light source and the sensor is approximately 13.6 metres.
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