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7.0 mol AgNo3 reacts with 3.0 mol Zn in a single replacement reaction. 2AgNo3 + Zn --> 2Ag + Zn(no3)2
How many moles of Zn(no3)2 form from 3.0 mol Zn?
mol Zn(NO3)2

User Kooshka
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1 Answer

4 votes
Answer:

n[(ZnNO3)2] = 3.0 mol

Step-by-step explanation:

The balanced chemical equation for the reaction is:

2AgNO3 + Zn → 2Ag + Zn(NO3)2

From the equation, we can see that 2 moles of AgNO3 react with 1 mole of Zn to produce 1 mole of Zn(NO3)2. Therefore, we can calculate the number of moles of Zn(NO3)2 formed from 7.0 moles of AgNO3 and 3.0 moles of Zn using the mole ratio:

Moles of Zn(NO3)2 = (moles of Zn) × (1 mole of Zn(NO3)2 / 1 mole of Zn)

Moles of Zn = 3.0 mol (given)

Moles of Zn(NO3)2 = 3.0 mol × (1 mol of Zn(NO3)2 / 1 mol of Zn) = 3.0 mol × 1 = 3.0 mol

Therefore, 3.0 moles of Zn(NO3)2 form from 3.0 moles of Zn.
User TTS
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