Answer:
n[(ZnNO3)2] = 3.0 mol
Step-by-step explanation:
The balanced chemical equation for the reaction is:
2AgNO3 + Zn → 2Ag + Zn(NO3)2
From the equation, we can see that 2 moles of AgNO3 react with 1 mole of Zn to produce 1 mole of Zn(NO3)2. Therefore, we can calculate the number of moles of Zn(NO3)2 formed from 7.0 moles of AgNO3 and 3.0 moles of Zn using the mole ratio:
Moles of Zn(NO3)2 = (moles of Zn) × (1 mole of Zn(NO3)2 / 1 mole of Zn)
Moles of Zn = 3.0 mol (given)
Moles of Zn(NO3)2 = 3.0 mol × (1 mol of Zn(NO3)2 / 1 mol of Zn) = 3.0 mol × 1 = 3.0 mol
Therefore, 3.0 moles of Zn(NO3)2 form from 3.0 moles of Zn.