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What was the initial pressure of a balloon that had an initial temperature of 124K but was pressurized to 200.6 kPa, reducing the temperature to 74K?,

1 Answer

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Answer:

P1 = 334.16 kPa

Step-by-step explanation:

We can use the combined gas law to solve this problem, which relates the initial pressure, temperature, and volume of a gas to its final pressure, temperature, and volume, assuming the number of moles of gas is constant.

The formula for the combined gas law is:

(P1 x V1) / T1 = (P2 x V2) / T2

where P1 is the initial pressure, V1 is the initial volume, T1 is the initial temperature, P2 is the final pressure, V2 is the final volume, and T2 is the final temperature.

We are given the initial temperature T1 = 124 K, the final temperature T2 = 74 K, and the final pressure P2 = 200.6 kPa. We want to find the initial pressure P1.

Assuming the volume of the balloon is constant, we can set V1 = V2, and the equation becomes:

P1 / T1 = P2 / T2

Substituting the values, we get:

P1 / 124 K = 200.6 kPa / 74 K

Solving for P1, we get:

P1 = (124 K / 74 K) x 200.6 kPa

P1 = 334.16 kPa

Therefore, the initial pressure of the balloon was 334.16 kPa.
User Bungles
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