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If ƒ (x) = 3x²+1 — 1, what is the value of f(−1), to the nearest ten-thousandth (if necessary)?

User Hidro
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1 Answer

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Answer:

To find the value of f(-1), we need to substitute -1 for x in the given function:

f(x) = 3x² + 1 - 1

f(-1) = 3(-1)² + 1 - 1

f(-1) = 3(1) + 0

f(-1) = 3

Therefore, f(-1) is equal to 3.

User Camala
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