Answer:
number of atoms = 2.31 × 10²³ atoms
Step-by-step explanation:
To calculate the number of atoms in 41.3 grams of Ag (silver), we need to use the Avogadro's number (6.022 × 10²³ atoms/mol).
First, we need to find the number of moles of Ag in 41.3 grams:
moles of Ag = mass of Ag / molar mass of Ag
moles of Ag = 41.3 g / 107.87 g/mol
moles of Ag = 0.383 mol
Next, we can use the Avogadro's number to calculate the number of atoms:
number of atoms = moles of Ag x Avogadro's number
number of atoms = 0.383 mol x 6.022 × 10²³ atoms/mol
number of atoms = 2.31 × 10²³ atoms
Therefore, there are 2.31 × 10²³ atoms in 41.3 grams of Ag.