135k views
0 votes
Deondra is going to invest $64,000 and leave it in an account for 5 years. Assuming the interest is compounded quarterly, what interest rate, to the nearest hundredth of a percent, would be required in order for Deondra to end up with $82,000?

2 Answers

0 votes

Answer:

To the nearest hundredth of a percent, an interest rate of 6.68% would be required for Deondra to end up with $82,000 after 5 years of compounding interest.

Step-by-step explanation:

We can use the formula for compound interest to solve this problem:

A = P(1 + r/n)^(nt)

where:

A = the final amount (in this case, $82,000)

P = the principal (the initial investment, in this case, $64,000)

r = the interest rate (what we're trying to find)

n = the number of times the interest is compounded per year (in this case, 4, since it's compounded quarterly)

t = the number of years (in this case, 5)

Plugging in the values we know and solving for r, we get:

$82,000 = $64,000(1 + r/4)^(4*5)

$82,000/$64,000 = (1 + r/4)^20

1.28125 = (1 + r/4)^20

Taking the 20th root of both sides, we get:

(1.28125)^(1/20) = 1 + r/4

0.0167 = r/4

r = 0.0668 (rounded to four decimal places)

Therefore, to the nearest hundredth of a percent, an interest rate of 6.68% would be required for Deondra to end up with $82,000 after 5 years of compounding interest.

User Rajapandian
by
7.2k points
5 votes

Final answer:

Deondra needs to calculate the interest rate to grow $64,000 to $82,000 in 5 years with compound interest compounded quarterly. The formula A = P(1 + r/n)^(nt) is used, with A being the future value, P the principal, r the interest rate, n the number of compounding periods per year, and t the time in years. After finding the interest rate, it is rounded to the nearest hundredth of a percent.

Step-by-step explanation:

Deondra needs to find the appropriate interest rate that would grow her investment of $64,000 to $82,000 in 5 years, with the interest being compounded quarterly. To solve this, we can use the compound interest formula:

A = P(1 + r/n)^(nt)

Where:

A is the amount of money accumulated after n years, including interest.

P is the principal amount (the initial amount of money).

r is the annual interest rate (in decimal form).

n is the number of times that interest is compounded per year.

t is the time the money is invested for, in years.

In Deondra's case, A is $82,000, P is $64,000, n is 4 (since interest is compounded quarterly), and t is 5 years. We need to find the interest rate r. The equation to solve is:

82000 = 64000(1 + r/4)^(4*5)

Now, we need to solve for r:

(82000/64000) = (1 + r/4)^20

(1.28125) = (1 + r/4)^20

We can then use logarithms to solve for r, and then convert the decimal into a percentage, rounding to the nearest hundredth of a percent.

After solving the equation, we would find the required quarterly compounded interest rate to achieve Deondra's financial goal.

User Stephen Docy
by
7.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.