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NO LINKS!! URGENT HELP PLEASE!!!!

If x < 0 and y > 0, determine the sign of the real number.

NO LINKS!! URGENT HELP PLEASE!!!! If x < 0 and y > 0, determine the sign of-example-1
User Flossfan
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Answer:

(a) The product xy is negative because one of the factors (x) is negative and the other factor (y) is positive. Therefore, the sign of xy is negative.

(b) The expression x^2y is also negative because x^2 is positive (the square of any real number is positive) and y is positive, so their product is positive. But since x is negative, the overall product is negative.

(c) The expression x/y + x can be written as (x/x)y + x, which simplifies to y + x. Since y is positive and x is negative, the sum y + x could be either positive or negative, depending on which absolute value is greater. If |y| > |x|, then y + x is positive. If |x| > |y|, then y + x is negative.

(d) The expression y-x is positive because y is greater than x and y is positive while x is negative. So the difference y-x is positive.

User Thelema
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