199k views
4 votes
10. How many moles are in 20 grams of Carbon (12 amu)?

11. How many moles are in 2.9 grams of Lithium (7 amu)?
12. How many moles are in 0.001 grams of Chlorine (35 amu)?
13. How many grams are in 10 moles of Beryllium (9 amu)?
14. How many grams are in 3.4 moles of Nitrogen (14 amu)?
15. How many grams are in 1.5 moles of Hydrogen (1 amu)?
16. How many atoms are in 10 moles of Helium?
17. How many atoms are in 0.003 moles of Neon?
18. How many atoms are in 2.7 moles of Sodium?
19. How many atoms are in 3.0 grams of Boron (9 amu)?
20. How many atoms are in 5.6 grams of Nitrogen?



i need help please for all of them

10. How many moles are in 20 grams of Carbon (12 amu)? 11. How many moles are in 2.9 grams-example-1
User Evanbikes
by
7.7k points

1 Answer

2 votes
10. To calculate the number of moles in 20 grams of Carbon (12 amu), we need to use the formula:
moles = mass / molar mass

The molar mass of carbon is 12 g/mol. Substituting the given values:

moles = 20 g / 12 g/mol

moles = 1.67 mol

Therefore, there are 1.67 moles of Carbon in 20 grams.

11. To calculate the number of moles in 2.9 grams of Lithium (7 amu), we need to use the formula:
moles = mass / molar mass

The molar mass of Lithium is 7 g/mol. Substituting the given values:

moles = 2.9 g / 7 g/mol

moles = 0.414 mol

Therefore, there are 0.414 moles of Lithium in 2.9 grams.

12. To calculate the number of moles in 0.001 grams of Chlorine (35 amu), we need to use the formula:
moles = mass / molar mass

The molar mass of Chlorine is 35 g/mol. Substituting the given values:

moles = 0.001 g / 35 g/mol

moles = 2.86 x 10^-5 mol

Therefore, there are 2.86 x 10^-5 moles of Chlorine in 0.001 grams.

13. To calculate the number of grams in 10 moles of Beryllium (9 amu), we need to use the formula:
mass = moles x molar mass

The molar mass of Beryllium is 9 g/mol. Substituting the given values:

mass = 10 mol x 9 g/mol

mass = 90 g

Therefore, there are 90 grams of Beryllium in 10 moles.

14. To calculate the number of grams in 3.4 moles of Nitrogen (14 amu), we need to use the formula:
mass = moles x molar mass

The molar mass of Nitrogen is 14 g/mol. Substituting the given values:

mass = 3.4 mol x 14 g/mol

mass = 47.6 g

Therefore, there are 47.6 grams of Nitrogen in 3.4 moles.

15. To calculate the number of grams in 1.5 moles of Hydrogen (1 amu), we need to use the formula:
mass = moles x molar mass

The molar mass of Hydrogen is 1 g/mol. Substituting the given values:

mass = 1.5 mol x 1 g/mol

mass = 1.5 g

Therefore, there are 1.5 grams of Hydrogen in 1.5 moles.

16. To calculate the number of atoms in 10 moles of Helium, we need to use Avogadro's number:
number of atoms = moles x Avogadro's number

Substituting the given values:

number of atoms = 10 mol x 6.022 x 10^23 atoms/mol

number of atoms = 6.022 x 10^24 atoms

Therefore, there are 6.022 x 10^24 atoms in 10 moles of Helium.

17. To find the number of atoms in 0.003 moles of neon, we can use Avogadro's number which is 6.022 x 10^23 atoms per mole.
Number of atoms = 0.003 moles x 6.022 x 10^23 atoms/mole
Number of atoms = 1.8066 x 10^21 atoms

Therefore, there are approximately 1.8066 x 10^21 atoms in 0.003 moles of neon.

18. To find the number of atoms in 2.7 moles of sodium, we can use Avogadro's number again.
Number of atoms = 2.7 moles x 6.022 x 10^23 atoms/mole
Number of atoms = 1.62654 x 10^24 atoms

Therefore, there are approximately 1.62654 x 10^24 atoms in 2.7 moles of sodium.

19. To find the number of atoms in 3.0 grams of boron, we need to first find the number of moles of boron using its atomic mass. The atomic mass of boron is 10.81 g/mol.
Number of moles = 3.0 g / 10.81 g/mol
Number of moles = 0.2773 mol

Then, we can use Avogadro's number to find the number of atoms.

Number of atoms = 0.2773 mol x 6.022 x 10^23 atoms/mole
Number of atoms = 1.6684 x 10^23 atoms

Therefore, there are approximately 1.6684 x 10^23 atoms in 3.0 grams of boron.

20. To find the number of atoms in 5.6 grams of nitrogen, we need to first find the number of moles of nitrogen using its atomic mass. The atomic mass of nitrogen is 14.01 g/mol.
Number of moles = 5.6 g / 14.01 g/mol
Number of moles = 0.3997 mol

Then, we can use Avogadro's number to find the number of atoms.

Number of atoms = 0.3997 mol x 6.022 x 10^23 atoms/mole
Number of atoms = 2.4066 x 10^23 atoms

Therefore, there are approximately 2.4066 x 10^23 atoms in 5.6 grams of nitrogen

Hope this helps!
User Ling Zhong
by
7.3k points