Answer:
To reflect a point over a vertical line x = c, where c is a constant, we can use the formula (2c - x, y).
Given the line of reflection x = -2, and the original points N(-5, 2), M(-2, 1), O(-3, 3), we can apply the formula as follows:
For N(-5, 2):
N' = (2(-2) - (-5), 2) = (1, 2)
For M(-2, 1):
M' = (2(-2) - (-2), 1) = (2, 1)
For O(-3, 3):
O' = (2(-2) - (-3), 3) = (1, 3)
So, the correct image vertices of N'M'O' after reflecting over x = -2 are N'(1, 2), M'(2, 1), O'(1, 3), which corresponds to the option:
N′(1, 2), M′(2, 1), O′(1, 3)
Please double-check to make sure if its right ;D