Answer:
The balanced chemical equation for the combustion of C2H4 (ethylene) is:
C2H4 + 3 O2 → 2 CO2 + 2 H2O
From the balanced chemical equation, we can see that 1 mole of C2H4 reacts to produce 2 moles of H2O.
First, we need to convert the given mass of C2H4 to moles using its molar mass. The molar mass of C2H4 is:
2(12.01 g/mol) + 4(1.01 g/mol) = 28.05 g/mol
Now, we can calculate the moles of C2H4:
moles of C2H4 = mass of C2H4 / molar mass of C2H4
moles of C2H4 = 16 g / 28.05 g/mol
moles of C2H4 ≈ 0.570 mol (rounded to three decimal places)
According to the balanced chemical equation, 1 mole of C2H4 produces 2 moles of H2O.
moles of H2O = 2 * moles of C2H4
moles of H2O = 2 * 0.570 mol
moles of H2O ≈ 1.140 mol (rounded to three decimal places)
Finally, we can convert the moles of H2O to grams using the molar mass of water (H2O), which is 18.015 g/mol.
mass of H2O = moles of H2O * molar mass of H2O
mass of H2O = 1.140 mol * 18.015 g/mol
mass of H2O ≈ 20.53 g (rounded to two decimal places)
So, approximately 20.53 grams of H2O will be produced by the combustion of 16 grams of C2H4.