Answer: the mass of 7.55 x 10^21 molecules of water is 0.226 g, which corresponds to option (c).
Explanation: The atomic weight of water (H2O) is:
2(1.008 g/mol) + 15.999 g/mol = 18.015 g/mol
Avogadro's number (NA) is:
6.022 x 10^23 molecules/mol
To calculate the mass of 7.55 x 10^21 particles of water, able to utilize the taking after equation:
mass = (number of atoms / Avogadro's number) x atomic weight
mass = (7.55 x 10^21 / 6.022 x 10^23) x 18.015 g/mol
mass = 0.226 g