The height is 230 feet after 9.125 seconds.
How do we calculate?
We have the equation that describes the height of the object as a function of time as:
h(t) = -16t^2 + 145t + 2
We input the values and simplify:
-16t^2 + 145t + 2 = 230
-16t^2 + 145t - 228 = 0
we can use the quadratic formula, to solve this quadratic equation,
t = (-b ± √(b^2 - 4ac)) / 2a
where a = -16, b = 145, and c = -228.
t = (-145 ± √(145^2 - 4(-16)(-228))) / 2(-16)
t = (-145 ± √ (21025)) / (-32)
t = (-145 ± 145) / (-32)
t = 0.625 seconds or t = 9.125 seconds
In conclusion, the height is 230 feet after 9.125 seconds.
#complete question:
An object is thrown upward at a speed of 145 feet per second by a machine from a height of 2 feet off the ground. The height h of the object after t seconds can be found using the equation
When will the height be 230 feet?