150k views
2 votes
B) d=22,4 mm d) d= 7 km f) r=0,5 hm h) r= ² kr km 3 C≈ C≈ C≈ C≈​

1 Answer

7 votes

The height is 230 feet after 9.125 seconds.

How do we calculate?

We have the equation that describes the height of the object as a function of time as:

h(t) = -16t^2 + 145t + 2

We input the values and simplify:

-16t^2 + 145t + 2 = 230

-16t^2 + 145t - 228 = 0

we can use the quadratic formula, to solve this quadratic equation,

t = (-b ± √(b^2 - 4ac)) / 2a

where a = -16, b = 145, and c = -228.

t = (-145 ± √(145^2 - 4(-16)(-228))) / 2(-16)

t = (-145 ± √ (21025)) / (-32)

t = (-145 ± 145) / (-32)

t = 0.625 seconds or t = 9.125 seconds

In conclusion, the height is 230 feet after 9.125 seconds.

#complete question:

An object is thrown upward at a speed of 145 feet per second by a machine from a height of 2 feet off the ground. The height h of the object after t seconds can be found using the equation

When will the height be 230 feet?

User Nwalton
by
8.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories