Answer: 199.68 grams of oxygen gas (O2) are needed to react with 85 grams of ammonia (NH3).
Explanation: The equilibrium chemical equation is as follows:
The chemical equation expressed as 4NH3 + 5O2 → 4NO + 6H2O is a representation of a chemical reaction that describes the reaction between four molecules of ammonia and five molecules of oxygen to yield four molecules of nitrogen monoxide and six molecules of water.
The stoichiometric analysis indicates that the reaction between oxygen and ammonia necessitates five moles of the former to react with four moles of the latter.
The present ratio can be employed for the computation of the requisite quantity of O2 necessary for the reaction with 85 grams of NH3, in the ensuing manner:
Determine the quantity of moles of NH3.
The molar mass of ammonia (NH3) can be calculated by adding the atomic masses of its constituent elements. The atomic mass of nitrogen (N) is 14.01 g/mol, and the atomic mass of hydrogen (H) is 1.01 g/mol. Therefore, the molar mass of NH3 is determined by adding the atomic mass of N to three times the atomic mass of H. Mathematically, the molar mass of NH3 is expressed as 14.01 g/mol + 3(1.01 g/mol), which yields a value of 17.04 g/mol.
The quantity of NH3 in moles can be determined by dividing the mass of NH3 by its corresponding molar mass, according to the fundamental principle of stoichiometry.
The number of moles of NH3 can be determined as 85 grams divided by the molar mass of NH3, which is 17.04 grams per mole.
The calculated value of the quantity represented by "moles of NH3" has been determined to be 4.99 mol, with insignificance beyond two decimal places due to rounding.
Determine the quantity of moles of O2 necessary.
The number of moles of O2 present is equivalent to five-fourths of the moles of NH3.
The amount of oxygen, represented by the unit of moles, can be mathematically expressed as (5/4) multiplied by 4.99 mol.
The quantity of oxygen, expressed in terms of moles, corresponds to 6.24 mol.
The conversion of moles of O2 to grams can be made by utilizing the molar mass of O2, which is 32 g/mol. This entails multiplying the given number of moles by the molar mass in order to obtain the corresponding mass in grams.
The molar mass of O2 was determined to be 32.00 g/mol, which was derived by multiplying 2 with the molar mass of oxygen, 16.00 g/mol.
The computation of the mass of O2 is achieved by multiplying the number of moles of O2 by the molar mass of O2.
The expression denoting the quantity of molecular oxygen, where mass is represented as a product of 6.24 moles and a molecular weight of 32.00 grams per mole, can be expressed in a manner consistent with academic writing.
The mass of O2 is 199.68 g.