Question

When lead (II) nitrate reacts with sodium iodide, sodium

nitrate and lead (II) iodide are formed. If you start with 25.0
grams of lead (II) nitrate and 15.0 grams of sodium iodide, how
many grams of sodium nitrate can be formed?

Answer 1

20.44 grams of sodium nitrate can be formed

Step-by-step explanation:

The balanced chemical equation for the reaction between lead (II) nitrate and sodium iodide is:

Pb(NO3)2 + 2NaI → 2NaNO3 + PbI2