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If the pressure exerted by a gas at 25ºC in a volume of 0.044L is 3.81atm, how many moles of gas are present?

1 Answer

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Answer: 0.00176 moles of gas present.

Step-by-step explanation:

We can use the Ideal Gas Law to solve for the number of moles of gas present:

PV = nRT

where:

P = pressure (in atm)

V = volume (in L)

n = number of moles

R = ideal gas constant (0.08206 L·atm/mol·K)

T = temperature (in Kelvin)

First, we need to convert the temperature from Celsius to Kelvin:

T = 25ºC + 273.15 = 298.15K

Plugging in the given values, we get:

(3.81 atm) (0.044 L) = n (0.08206 L·atm/mol·K) (298.15 K)

Solving for n, we get:

n = (3.81 atm x 0.044 L) / (0.08206 L·atm/mol·K x 298.15 K)

n = 0.00176 mol

Therefore, there are 0.00176 moles of gas present.

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