Final answer:
The value of Ksp for Ag2SO4 is 0.0173 M.
Step-by-step explanation:
The value of Ksp for Ag2SO4 can be calculated using the given information. We know that solubility is defined as the amount of solute that can dissolve in a given amount of solvent. In this case, 5.40g of Ag2SO4 dissolves in 1.00 L of water. To find the molar solubility, we need to convert the mass of Ag2SO4 to moles and divide by the volume of water.
Molar mass of Ag2SO4 = 2(107.87 g/mol) + 32.07 g/mol + 4(16.00 g/mol) = 311.81 g/mol
Moles of Ag2SO4 = mass/volume = 5.40 g / 311.81 g/mol = 0.0173 mol
Molar solubility = moles/volume = 0.0173 mol / 1.00 L = 0.0173 M