Question

The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room. Which equations can be used to solve for y, the length of the room? Select three options. y(y + 5) = 750 y2 – 5y = 750 750 – y(y – 5) = 0 y(y – 5) + 750 = 0 (y + 25)(y – 30) = 0

Answer 1

• y² -5y = 750
• 750 -y(y -5) = 0
• (y +25)(y -30) = 0

Explanation:

You want three equations that can be used to solve for the length (y) of a room that is whose width is 5 feet less than its length and whose area is 750 square feet.

Area

The area of the room is the product of its length and width. We are given that the length is y, so the width is (y-5) and that product is ...

A = LW

750 = y(y -5)

This equation can be rearranged into several different forms:

y² -5y = 750 . . . . . . . multiply it out

750 -y(y -5) = 0 . . . . . subtract the right side expression

(y +25)(y -30) = 0 . . . . factor it