To calculate the number of moles in a given number of molecules of a compound, we can use the Avogadro's number, which is approximately 6.022 x 10^23 particles per mole.
First, we need to determine the number of moles of Li2O in 12,360 molecules:
1 mole of Li2O = 2 moles of Li atoms + 1 mole of O atoms
The molecular formula of Li2O tells us that each molecule contains 2 Li atoms and 1 O atom.
So, the total number of Li atoms in 12,360 Li2O molecules is:
2 Li atoms/molecule x 12,360 molecules = 24,720 Li atoms
And the total number of O atoms in 12,360 Li2O molecules is:
1 O atom/molecule x 12,360 molecules = 12,360 O atoms
Next, we can calculate the number of moles of Li and O atoms separately using the Avogadro's number:
Number of moles of Li atoms = (24,720 atoms) / (6.022 x 10^23 atoms/mole) = 4.11 x 10^-20 moles
Number of moles of O atoms = (12,360 atoms) / (6.022 x 10^23 atoms/mole) = 2.05 x 10^-20 moles
Since Li2O contains 2 Li atoms and 1 O atom per molecule, we can see that the limiting reactant is O, and we have 2.05 x 10^-20 moles of Li2O.
Therefore, the answer is that there are approximately 2.05 x 10^-20 moles of Li2O in 12,360 molecules of Li2O.