Question

A steel reaction vessel of a bomb calorimeter has a volume of 0.193 L, is charged with oxygen gas to a pressure of 28.3 atm at 24.5oC. Calculate the moles of oxygen in the reaction vessel.

Answer 1

To calculate the moles of oxygen in the reaction vessel, we will use the ideal gas law, which states:

PV = nRT

where P is the pressure in atmospheres, V is the volume in liters, n is the number of moles, R is the gas constant (0.0821 L·atm/mol·K), and T is the temperature in Kelvin.

Is the temperature in Kelvin. First, we need to convert the temperature from Celsius to Kelvin:

T = 24.5oC + 273.15 = 297.65 K

Now we can plug in the values we know:

28.3 atm * 0.193 L = n * 0.0821 L·atm/mol·K * 297.65 K

Simplifying this equation, we get:

n = (28.3 atm * 0.193 L) / (0.0821 L·atm/mol·K * 297.65 K)

n = 0.0228 mol

Therefore, there are 0.0228 moles of oxygen in the reaction vessel.