Answer:
Step-by-step explanation:
To find the number of atoms present in 8.500 mole of chlorine atoms, we can use Avogadro's number, which states that one mole of any substance contains 6.022 x 10^23 particles. Therefore, 8.500 moles of chlorine atoms would contain:
8.500 moles x 6.022 x 10^23 atoms/mole = 5.1207 x 10^24 atoms of chlorine
To determine the mass (g) of 15.50 mole of oxygen, we can use the molar mass of oxygen, which is 16.00 g/mol. Therefore, the mass of 15.50 moles of oxygen would be:
15.50 moles x 16.00 g/mol = 248 g of oxygen
To determine the number of moles of helium in 1.953 x 10^8 g of helium, we can use the molar mass of helium, which is 4.00 g/mol. Therefore, the number of moles of helium would be:
1.953 x 10^8 g / 4.00 g/mol = 4.883 x 10^7 moles of helium
To calculate the number of atoms in 147.82 g of sulfur, we first need to find the number of moles of sulfur using the molar mass of sulfur, which is 32.06 g/mol. Therefore, the number of moles of sulfur would be:
147.82 g / 32.06 g/mol = 4.604 moles of sulfur
Next, we can use Avogadro's number to find the number of atoms in 4.604 moles of sulfur:
4.604 moles x 6.022 x 10^23 atoms/mole = 2.772 x 10^24 atoms of sulfur
The molar mass of Co (cobalt) can be found on the periodic table, which is 58.93 g/mol.
To determine the formula mass of Ca3(PO4)2, we need to find the sum of the masses of all the atoms in the formula. The molar masses of Ca, P, and O can be found on the periodic table:
Ca: 40.08 g/mol
P: 30.97 g/mol
O: 16.00 g/mol
Ca3(PO4)2 would contain:
3 atoms of Ca: 3 x 40.08 g/mol = 120.24 g/mol
2 atoms of P: 2 x 30.97 g/mol = 61.94 g/mol
8 atoms of O: 8 x 16.00 g/mol = 128.00 g/mol
Adding these masses together gives us:
120.24 g/mol + 61.94 g/mol + 128.00 g/mol = 310.18 g/mol
Therefore, the formula mass of Ca3(PO4)2 is 310.18 g/mol.