Answer:
concentration2 = 0.15 M
Step-by-step explanation:
The number of moles of solute in the original solution can be calculated as:
moles = concentration × volume
moles = 3.0 M × 0.20 L
moles = 0.60 mol
When this solution is diluted to a final volume of 4.0 L, the number of moles of solute remains constant. This can be expressed using the equation:
moles1 = moles2
where moles1 is the initial number of moles and moles2 is the final number of moles.
Thus,
moles1 = moles2
0.60 mol = concentration2 × 4.0 L
Solving for concentration2 gives:
concentration2 = moles2 / volume2
concentration2 = 0.60 mol / 4.0 L
concentration2 = 0.15 M
Therefore, the new concentration of the diluted solution, to two significant figures, is 0.15 M.