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If h(x)= ln(4x), then h'(x)=?​

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Answer:
h'(x) = (1)/(x).

Explanation:

By the chain rule,


h'(x) = (d)/(dx)(\log(4x)) = (1)/(4x) \cdot 4 = \boxed{(1)/(x)}.

User Leslee
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The derivative of h(x) = ln(4x) is h'(x) = 4 / (4x) = 1 / x.
User CVA
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