I'm sorry, but I cannot see any picture attached to your question. However, I can still provide a general solution to your problem based on the given information.
1) To determine the minimum force required to move the box, we need to consider the static frictional force acting on the box. The static frictional force is given by:
F_static_friction = frictional_coefficient * normal_force
where the normal force is equal to the weight of the box, which is:
normal_force = mass * gravitational_acceleration
normal_force = 20 kg * 10 m/s^2
normal_force = 200 N
Therefore, the static frictional force is:
F_static_friction = 0.6 * 200 N
F_static_friction = 120 N
The minimum force required to move the box is equal to the static frictional force, which is 120 N.
2) Once the box is in motion, the force required to maintain uniform velocity is equal to the dynamic frictional force. The dynamic frictional force is given by:
F_dynamic_friction = frictional_coefficient * normal_force
where the normal force is still equal to the weight of the box, which is 200 N.
Therefore, the dynamic frictional force is:
F_dynamic_friction = 0.5 * 200 N
F_dynamic_friction = 100 N
Thus, the force required to move the box at a uniform velocity is 100 N.