105k views
4 votes
Find three consecutive integers such that four times the first added to the third is 92

SOLVE QUICKLY
Thanks​

User Madnx
by
9.1k points

2 Answers

2 votes

Answer: the three consecutive integers are 18, 19, and 20.

Explanation:

User Allo
by
8.7k points
4 votes

Answer:

18, 19, and 20

Explanation:

let the first integer be 'x'.

Thus, the three consecutive integers are:

x, (x+1), (x+2).

Therefore, if 4 × x added to (x+2) = 92, then:


(x+2)+4x=92\\5x+2=92\\5x=90\\x=18

Hence x = 18, and thus, the three consecutive integers are 18, 19, and 20.

User Natiiix
by
7.7k points

No related questions found