Find three consecutive integers such that four times the first added to the third is 92 SOLVE QUICKLY Thanks

Question

asked Apr 16, 2024 105k views

2 Answers

Natiiix · Answer 1 · 2024-04-23T07:15:33+0000

Answer:

18, 19, and 20

Explanation:

let the first integer be 'x'.

Thus, the three consecutive integers are:

x, (x+1), (x+2).

Therefore, if 4 × x added to (x+2) = 92, then:

$(x+2)+4x=92\\5x+2=92\\5x=90\\x=18$

Hence x = 18, and thus, the three consecutive integers are 18, 19, and 20.