Question

Find three consecutive integers such that four times the first added to the third is 92

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Answer 1

Answer: the three consecutive integers are 18, 19, and 20.

Explanation:

Answer 2

18, 19, and 20

Explanation:

let the first integer be 'x'.

Thus, the three consecutive integers are:

x, (x+1), (x+2).

Therefore, if 4 × x added to (x+2) = 92, then:

`(x+2)+4x=92\\5x+2=92\\5x=90\\x=18`

Hence x = 18, and thus, the three consecutive integers are 18, 19, and 20.