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What is the wavelength of a photon with energy 8.87x10-28J? Answer to 3 significant figures: ___ ___ ___?

User MatuDuke
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Answer: the wavelength of the photon is approximately 3.58 × 10^-18 meters.

Explanation: where E is the energy of the photon, h is Planck's constant, f is the frequency of the photon, c is the speed of light, and λ is the wavelength of the photon.

We can rearrange this equation to solve for the wavelength:

λ = hc/E

where all variables have their previously defined meanings.

First, we need to convert the energy from joules to electronvolts (eV), which is a more commonly used unit for photon energy:

8.87 × 10^-28 J = 8.87 × 10^-28 J / 1.602 × 10^-19 J/eV = 5.53 × 10^-10 eV

Next, we can substitute the given values into the equation:

λ = (6.626 × 10^-34 J s) × (2.998 × 10^8 m/s) / (5.53 × 10^-10 eV)

Simplifying, we get:

λ = 3.580 × 10^-18 m

Finally, we can express the wavelength in scientific notation with three significant figures:

λ = 3.58 × 10^-18 m

User Yogendra Chauhan
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