Answer: 84 g of N2 reacts completely to form 102 g of NH3.
Explanation: Change over the mass of N2 from grams to moles utilizing its molar mass:
84 g N2 × (1 mol N2 / 28 g N2) = 3 moles of N2
Utilize stoichiometry to calculate the number of moles of NH3 delivered, knowing that 3 moles of H2 are required to respond with 1 mole of N2:
3 moles of N2 × (2 moles of NH3 / 1 mole of N2) = 6 moles of NH3
Change over the number of moles of NH3 to grams utilizing its molar mass:
6 moles of NH3 × (17 g NH3 / 1 mol NH3) = 102 g NH3