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A pre-image has coordinates N(3, -2), A(5, 0) and P(2, 4). The image has coordinates N’ (2, 0), A'(4, 2) and P'(1, 6). Write a transformation rule to describe the path the pre-image made to arrive at the image.

User Iskren
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Answer:

f(x + 1) + 2

Explanation:

All the points are translated 1 unit to the left and 2 units up.
To write a translation along the x-axis, movement to the right would be written as f(x - a), where a is the amount translated, and movement to the left would be written as f(x + a). In this case, we would need to write the translation as f(x + 1), since it is moving 1 unit to the left.
As for translations along the y-axis, movement upward would be written as f(x) + a, and movement downward would be written as f(x) - a. Thus, the transformation rule to describe the path the pre-image made to arrive at the image would be f(x + 1) + 2.

P.S. I'm a bit rusty with this stuff, so I apologize in advance if I messed something up.

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