Answer: 239/94Pu → 239/95Am + 0/-1e
Explanation: The present chemical transformation involves the conversion of a neutron residing in the nucleus of the element Plutonium-239 to a proton, accompanied by the release of an electron by beta decay. The subatomic particle known as the proton remains confined within the atomic nucleus, thereby triggering a metamorphosis of the constituent element, resulting in the creation of Am-239. Meanwhile, the emission of a beta particle occurs from the nucleus.