Answer:
To solve this problem, we need to integrate the derivative f'(x) to obtain the function f(x).
∫f'(x) dx = ∫(4x - 3) dx
f(x) = 2x^2 - 3x + C
where C is the constant of integration.
To find the value of C, we need to use the fact that f(0) = 5. Substituting x = 0 into the above equation, we get:
f(0) = 2(0)^2 - 3(0) + C = C
Therefore, C = 5.
Hence, the function f(x) is:
f(x) = 2x^2 - 3x + 5
Now, we can find f(5) and f(-1) and compute their difference:
f(5) - f(-1) = (2(5)^2 - 3(5) + 5) - (2(-1)^2 - 3(-1) + 5)
f(5) - f(-1) = (50 - 15 + 5) - (2 + 3 + 5)
f(5) - f(-1) = 35 - 10
f(5) - f(-1) = 25
Therefore, f(5) - f(-1) = 25.