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X2 - 12x + 8 = 0 by completing the square

User Nikhilweee
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1 Answer

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To solve x^2 - 12x + 8 = 0 by completing the square, we can follow these steps:

Move the constant term to the right side:

x^2 - 12x = -8

Take half of the coefficient of x, square it, and add it to both sides of the equation:

x^2 - 12x + (-12/2)^2 = -8 + (-12/2)^2

Simplifying the right side:

x^2 - 12x + 36 = -8 + 36

Factor the left side:

(x - 6)^2 = 28

Take the square root of both sides:

x - 6 = ±√28

Add 6 to both sides:

x = 6 ±√28

Simplify the roots:

x = 6 ±2√7

Therefore, the solutions to the equation x^2 - 12x + 8 = 0 by completing the square are x = 6 + 2√7 and x = 6 - 2√7.

User Asaf Hanish
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