Question

Find the volume of this sphere.

Use 3 for TT.
-d=6in
V ≈ [?] in ³
V = πr³
Enter

Answer 1

Answer: Spheres aren’t three-dimensional—they are two-dimensional. This is evident from the fact that in order to specify a point on a sphere, you only need two pieces of information, such as latitude and longitude.

If you include the interior of the sphere, this is instead called a closed ball, and that is three-dimensional. You can specify a point in the closed ball in all sorts of different ways; one of the most convenient would be latitude, longitude, and distance from the center. However, other than convenience, there is no reason to prefer one coordinate system over any other.

(This fact has nothing to do with spheres or closed balls—that is just a statement that is generally true. People who insist that “the three dimensions” are length, width, and height don’t know what they are talking about.)

Explanation:

Answer 2

If the volume formula is from the question it would 3*(6/2)^3 =27 because the radius is diameter divided by 2 but if it’s the formula I know which 4/3 pie (r)^3 it would be 4/3(3)(3)^3 =36