To subtract (c-3d-e) from the sum of (4c+d-e) and (2c-3d+2e), we can first find the sum of the two polynomials, which is (4c+d-e) + (2c-3d+2e) = 6c - 2d + e. Then, we can subtract (c-3d-e) from this sum by changing the signs of the terms in (c-3d-e) and adding the resulting polynomial to 6c - 2d + e. This gives us:
(4c+d-e) + (2c-3d+2e) - (c-3d-e) = 5c + d + 4e
Therefore, the answer is 5c + d + 4e.