86.3k views
0 votes
A ball is dropped from a height of 32 m.

With each bounce, the ball reaches a
height that is half the height of
the previous bounce. After
which bounce will the ball
rebound to a maximum
height of 25 cm?

1 Answer

6 votes
Let's first convert the maximum height of 25 cm to meters:

25 cm = 0.25 m

Let's represent the number of bounces as "n". We know that with each bounce, the ball reaches a height that is half the height of the previous bounce. Therefore, the height of the nth bounce can be represented as:

32 x (1/2)^n

We want to find the bounce where the ball rebounds to a maximum height of 0.25 m. So we can set up an equation:

32 x (1/2)^n = 0.25

Simplifying this equation, we get:

(1/2)^n = 0.25/32

(1/2)^n = 0.0078125

Taking the logarithm of both sides with base 0.5, we get:

n = log0.5(0.0078125)

n = 7.0

Therefore, the ball will rebound to a maximum height of 25 cm after 7 bounces.
User TehK
by
8.3k points