Question

PLEASE ANSWER 30 POINTS!!!

What mass of AI2O3 forms from 54 g AI and excess oxygen?
4AI + 3O2 ---> 2AI2O3
AI: 27 g/mol AI2O3: 102 g/mol
54 g AI ---> gAI2O3

Answer 1

108g/mol

Step-by-step explanation:

Equation: 4Al + 3O2 ----> 2Al2O3

Ratios. : 4. : 3. : 2

4 moles of Al give 2 moles of Al2O3

4*27g of Al gives 2*102g of Al2O3

108g of Al gives 204g of Al2O3

54g of Al will give = (54*204)/108g of Al2O3

Ans:108g/mol