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Justin says that x^-2and -x² are equivalent. Is he
correct? Justify your answer.

User R Pelzer
by
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1 Answer

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~\hspace{7em}\textit{negative exponents} \\\\ a^(-n) \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^(-n)} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^(-m)\implies a^(n-m) \\\\[-0.35em] ~\dotfill\\\\ x^(-2)\implies \cfrac{1}{x^2}\hspace{5em} {\Large \begin{array}{llll} \\e \end{array}}\hspace{5em}-x^2

User Maurice Kelly
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