Question

Please answer this geometry question

Answer 1

Check the picture below.

`\tan(52^o )=\cfrac{\stackrel{opposite}{y}}{\underset{adjacent}{120}}\implies 120\tan(52^o )=y \\\\[-0.35em] ~\dotfill\\\\ \sin(67^o )=\cfrac{\stackrel{opposite}{y}}{\underset{hypotenuse}{CB}}\implies CB=\cfrac{y}{\sin(67^o )} \\\\\\ CB=\cfrac{120\tan(52^o )}{\sin(67^o )}\implies CB\approx 166.9 ~~ ft`

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