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Find the value of the indicated trigonometry ratio cos in right tringle with side of 6,6*squort 2, 6*squort 3

User SmartTom
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1 Answer

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Answer:√2/2

Explanation:

Let's label the sides of the right triangle as follows:

The side adjacent to the angle θ (cosine is adjacent/hypotenuse): 6

The hypotenuse (the longest side): 6√2

The side opposite to the angle θ (sine is opposite/hypotenuse): 6√3

Using the Pythagorean theorem, we can find the length of the missing side:

a² + b² = c²

6² + (6√3)² = (6√2)²

36 + 108 = 72

144 = 72

√144 = √72

12 = 6√2

Now that we know the length of all three sides, we can use the cosine ratio to find the value of cos(θ):

cos(θ) = adjacent/hypotenuse = 6/6√2 = √2/2

Therefore, the value of cos(θ) in the right triangle with sides of 6, 6√2, and 6√3 is √2/2.

User Soula
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