Answer:
See explanation
Explanation:
We have that;
P(t) = (25t2 + 150t + 100)/(t2 + 6t + 24)
a) rate at which Glen Cove's population is changing with respect to time.
dP/dt = (t^2 + 5t + 40) (50t + 125) - (25t^2 + 125t + 200) (2t + 5)/(t^2 + 5t + 40)^2
dP/dt = 1000t + 3000/(t^2 + 6t + 24)^2
b) population after 10 years
P(t) = (25t2 + 150t + 100)/(t2 + 6t + 24)
P(t) =(25(10)^2 + 150(10) + 100)/((10^2 + 6(10) + 24)
P(t) = 4100/184
P(t) = 22283
c) when t = 10
dP/dt = 1000t + 3000/(t^2 + 6t + 24)^2
dP/dt = 1000(10) + 3000/(10^2 + 6(10) + 24)^2
dP/dt = 13000/33856
dP/dt = 0.384