what is the concentration of a solution formed by diluting 5.00 ml of a 3.20 m glucose solution to 40.0 ml?

asked Sep 26, 2024 53.9k views

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Answer:

0.413 M

Step-by-step explanation:

Use M1V1 = M2V2

(3.30M)x(5.00mL) = M2x(40.0mL)

M2 = .4125 M

.413 M

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