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If 64 grams of O2 is at a volume of 17L, how many moles will it occupy at 12 L.

___moles

1 Answer

4 votes

Answer:

Step-by-step explanation:

17L - 64grams

12L - x grams (where x = mass at 12L)

X =
(12*64)/(17)

x =
(768)/(17)

x = 45.2g

moles,n = mass,m/ molar mass

molar mass of O2 = 16*2 = 32

moles, n =
(45.2)/(32)

moles, n = 1.4125 mol

Therefore O2 occupys 1.4125moles at 12L

User AlokeT
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