Answer:
Step-by-step explanation:
17L - 64grams
12L - x grams (where x = mass at 12L)
X =
x =
x = 45.2g
moles,n = mass,m/ molar mass
molar mass of O2 = 16*2 = 32
moles, n =
moles, n = 1.4125 mol
Therefore O2 occupys 1.4125moles at 12L
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