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What is an equation of the line that is perpendicular to y + 1 = -3(x-5) and passes through the point (4,-6)?

What is an equation of the line that is perpendicular to y + 1 = -3(x-5) and passes-example-1
User Olliezhu
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2 Answers

7 votes

Answer:

y + 6 = 1/3 (x-4)

Explanation:

What is an equation of the line that is perpendicular to y + 1 = -3(x-5) and passes-example-1
User JoergB
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5 votes


\boxed{\bold{y + 6 = (1)/(3) (x - 4)}}

Replace the second y (y1) and the 2nd x (x1) with the new points and then -3 become 1/3 due to perpendicular meaning opposite reciprocal (2/3 reciprocal is 3/2 and the opposite would be its negative, -3/2, for example)

So there's your answer plus some info for future knowledge

User Anirudh Goel
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